【1】f[x]=x[x+1][x+2].[x+100][2]f[x]=a0 x^n+a1 x^[n-1]+.a[n-1]x+ an
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【1】f[x]=x[x+1][x+2].[x+100][2]f[x]=a0x^n+a1x^[n-1]+.a[n-1]x+an【1】f[x]=x[x+1][x+2].[x+100][2]f[x]=a0x
【1】f[x]=x[x+1][x+2].[x+100][2]f[x]=a0 x^n+a1 x^[n-1]+.a[n-1]x+ an
【1】f[x]=x[x+1][x+2].[x+100]
[2]f[x]=a0 x^n+a1 x^[n-1]+.a[n-1]x+ an
【1】f[x]=x[x+1][x+2].[x+100][2]f[x]=a0 x^n+a1 x^[n-1]+.a[n-1]x+ an
（1）f(x)=x（x＋1）（x＋2）（x＋3）．．．．．．（x＋100）
lnf(x)=lnx+ln(x+1)+ln(x+2)+...+ln(x+100)
[lnf(x)]'=f'(x)/f(x)=1/(x)+1/(x+1)+1/(x+2)+.+1/(x+100)
所以,
f'(x)=f(x)×[1/(x)+1/(x+1)+1/(x+2)+...+1/(x+100)]
（2）f(x)=a0 x^n+a1 x^[n-1]+.a[n-1]x+ an
f'(x)=n×a0×x^(n-1)＋(n-1)×a1×x^(n-2)＋……＋a(n-1)
两边对x求导:
y' + [(1/2)/√(x +y)](x + y)'] = 1
y' + [(1/2)/√(x +y)](1 + y')] = 1
f(x)={2x+1,x
f(x)={1+x/2,x
f(x)=(x-1)/(x+2)
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