log a b=log b a,则:ab=?a不等于b
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logab=logba,则:ab=?a不等于blogab=logba,则:ab=?a不等于blogab=logba,则:ab=?a不等于b应该有个a≠b吧,ab=1logab=lnb/lnalogba
log a b=log b a,则:ab=?a不等于b
log a b=log b a,则:ab=?
a不等于b
log a b=log b a,则:ab=?a不等于b
应该有个a≠b吧,ab=1
log a b=lnb/lna
log b a=lna/lnb
因为log a b=log b a
所以lnb/lna=lna/lnb
(lnb)^2=(lna)^2
lnb=lna 或者lnb=-lna
因为a≠b
所以lna=-lnb
得到lna+lnb=0
ln(ab)=0
所以ab=1
log a b=log b a,则:ab=?a不等于b
已知 log (a) ab=1/p ,则 log (ab) a/b=__ __.
log(2)5=a,log(2)7=b用ab表示log(35)28
关于数学对数的换底公式推论的问题已知 log(2)(3) = a,log(3(7)=b,用a,b表示log(42)(56)因为log(2)(3)=a,则1/a=log(3)(2),又∵log(3)(7)=b,∴log(42)(56)=log(3)(56)/log(3)(42)=log(3)(7)+3·log(3)(2)/log(3)(7)+log(3)(2)+1=ab+3/ab+b+1
关于数学对数的换底公式推论的问题已知 log(2)(3) = a,log(3(7)=b,用a,b表示log(42)(56)因为log(2)(3)=a,则1/a=log(3)(2),又∵log(3)(7)=b,∴log(42)(56)=log(3)(56)/log(3)(42)=log(3)(7)+3·log(3)(2)/log(3)(7)+log(3)(2)+1=ab+3/ab+b+1
log a c+log b c=0(c≠1),则ab+c-abc=?
log a c+log b c=0(c≠1),则ab+c-abc=?
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