log a c+log b c=0(c≠1),则ab+c-abc=?

log a c+log b c=0(c≠1),则ab+c-abc=? log a c+log b c=0(c≠1),则ab+c-abc=? log(a)(b)=log(c)(b) /log(c)(a) 怎么证log(a)(b)=log(c)(b) /log(c)(a)怎么证 log(a)b=log(c)b/log(c)a 是怎么推算来的 2log(b)x=log(a)x+log(c)x求证,c^2=(ac)^[log(a)b] 1≤a≤b≤c,证明log(a)(b)+log(b)(c)+log(c)(a)≤log(b)(a)+log(c)(b)+log(a)(c) 已知ab=c(a>0,b>0且c≠1),log(c)b=x,试用x表示log(c)a那个c是底数. 对数函数题 log a - log b = 3 log (c/2) 求 a = ______________ log a b*log b c=log b b*log a c成立吗中间的字母是写在下面的 相当于log的脚码 不等式取对数的推导过程设A ,B>0,A>B则log(c)A>log(c)B,我推到:令x=log(c)A,y=log(c)B则A=c^x,B=c^y,有c^x < c^y显然x < y但不知道咋用纯粹的数学语言表达出x < y就是推出log(c)A>log(c)B，我是另x=log(c)A,y=log(c)B， 用C语言计算log(5)log(3)-log(2))/sin(π/3)=#include #includeint main(){int a=5,b=3,c=2;double y;y=(log(a)log(b)-log(c))/sin(π/b);printf((log(5)log(3)-log(2))/sin(π/3)=%ld,y);return 0;}x这哪里错了? 利用换底公式证明：log(a)b.log(b)c.log(c)a=1rt.是乘号 log a b=log c b/log c a 这个定理是怎么用定义推导出来的 a^[log(a)b×log(b)c×log(c)N]求值 求对数的解答题!求值.log(b)A*log(c)B*log(a)C 27-1/ 若a>0,b>0,a*b>1,log(1/2)[a]=ln2,则log(a)[b]与log(1/2)[a]的关系是：（）?(A)log(a)b< log(1/2)[a](B)log(a)b= log(1/2)[a](C)log(a)b>log(1/2)[a](D)log(a)b与log(1/2)[a] 无法比较大小我做到一半就做不下去了：a=(1/2)^(ln2)log logab为什么等于logcb/logcalog a B=log c B / log c A 求证明 a^(log(c)(b))=b(log(c)(a))