cos(-29π/6)的值为?
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cos(-29π/6)的值为?cos(-29π/6)的值为?cos(-29π/6)的值为?原式=cos(-6π+7π/6)=cos(7π/6)=cos(π+π/6)=-cos(π/6)=-√3/2
cos(-29π/6)的值为?
cos(-29π/6)的值为?
cos(-29π/6)的值为?
原式=cos(-6π+7π/6)
=cos(7π/6)
=cos(π+π/6)
=-cos(π/6)
=-√3/2
cos(-29π/6)的值为?
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