题目见下图,先谢过了!

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题目见下图,先谢过了!题目见下图,先谢过了!题目见下图,先谢过了!card(A∪B∪C)=card[(A∪B)∪C]=card(A∪B)+card(C)-card[(A∪B)∩C]=card(A)+c

题目见下图,先谢过了!
题目见下图,先谢过了!

题目见下图,先谢过了!
card(A∪B∪C)
=card[(A∪B)∪C]
=card(A∪B)+card(C)-card[(A∪B)∩C]
=card(A)+card(B)-card(A∩B)+card(C)-card[(A∩C)∪(B∩C)]
=card(A)+card(B)-card(A∩B)+card(C)-card(A∩C)-card(B∩C)+card(A∩C∩B∩C)
=card(A)+card(B)+card(C)-card(A∩B)-card(A∩C)-card(B∩C)+card(A∩B∩C)