设(x+y)(x-2+y)=35,求x+y的值
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设(x+y)(x-2+y)=35,求x+y的值设(x+y)(x-2+y)=35,求x+y的值设(x+y)(x-2+y)=35,求x+y的值(x+y)(x-2+y)=35(x+y)(x+y-2)=35(
设(x+y)(x-2+y)=35,求x+y的值
设(x+y)(x-2+y)=35,求x+y的值
设(x+y)(x-2+y)=35,求x+y的值
(x+y)(x-2+y)=35
(x+y)(x+y-2)=35
(x+y)^2-2(x+y)-35=0
(x+y-7)(x+y+5)=0
所以：
x+y=7或者
x+y=-5
(x+y)(x-2+y)=35；
(x+y)²-2(x+y)-35=0;
(x+y-7)(x+y+5)=0;
x+y=7或x+y=-5；
(x+y)(x-2+y)=35
(x+y)²-2(x+y)-35=0
(x+y+5)(x+y-7)=0
x+y=-5或x+y=7
(x+y)(x-2+y)=35
(x+y)^2-2(x+y)-35=0
(x+y-7)(x+y+5)=0
x+y=7或x+y=-5
x+y=7,把x+y看成一个整体可用t替换,即t.(t-2)=35
设x+y=t
则：t（t-2）=35
之后就会做了吧~~
x+y=7 （-5）
设(x+y)(x-2+y)=35,求x+y的值
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