数列{an}满足 11/9 a1 + (11/9)^2 a2 + ...+ (11/9)^n an = 1/2 (n^2+n) 当an取得最大值时,n等于?
来源:学生作业帮助网 编辑:六六作业网 时间:2025/01/09 08:31:56
数列{an}满足11/9a1+(11/9)^2a2+...+(11/9)^nan=1/2(n^2+n)当an取得最大值时,n等于?数列{an}满足11/9a1+(11/9)^2a2+...+(11/9
数列{an}满足 11/9 a1 + (11/9)^2 a2 + ...+ (11/9)^n an = 1/2 (n^2+n) 当an取得最大值时,n等于?
数列{an}满足 11/9 a1 + (11/9)^2 a2 + ...+ (11/9)^n an = 1/2 (n^2+n) 当an取得最大值时,n等于?
数列{an}满足 11/9 a1 + (11/9)^2 a2 + ...+ (11/9)^n an = 1/2 (n^2+n) 当an取得最大值时,n等于?
11/9 a1=1/2 (1^2+1)
a1=9/11
11/9 a1 + (11/9)^2 a2 + ...+ (11/9)^n an = 1/2 (n^2+n)
11/9 a1 + (11/9)^2 a2 + ...+ (11/9)^(n-1) a(n-1) = 1/2 ((n-1)^2+(n-1))
可得(11/9)^n an =n
an=n*(9/11)^n
然后便是利用函数单调性了……可用求导法或定义法
得到n=5时an最大
数列an满足a1=2,an+1=4an+9,则an=?
已知数列{an}满足3an+1+an=4,a1=9,求通项公式.
数列{An}满足a1=1/2,a1+a2+..+an=n方an,求an
数列{an}满足 11/9 a1 + (11/9)^2 a2 + ...+ (11/9)^n an = 1/2 (n^2+n) 当an取得最大值时,n等于?
已知数列{an}满足a1=1 an+1=an/(3an+1) 则球an
数列 (10 18:35:56)设数列{an}满足a1=9,an+1=-1/2an+3,求an的通项公式(含过程)
已知数列{an}满足an+1=an+n,a1等于1,则an=?
数列{an}满足a1=1 an+1=2n+1an/an+2n
已知数列{an}满足an+1=2an+3.5^n,a1=6.求an
数列an满足a1=2,an+1=an²求an
数列an满足a1=2,an+1=an²求an
数列[An]满足An+1-An+3=0,且A1=-5.求An.
数列{an}满足a1=1,且an=an-1+3n-2,求an
已知数列{an}满足a1+a2+...+an=n²an求其通项an
已知数列{an}满足:a1=9, 3a(n+1 )+an=4,求通项公式
递增数列{an}满足a1=6,an+an-1=9/an-an-1+8(n>=2)则a70=
已知数列{an}满足3an+1+an=4,a1=9,前n项和为sn,则满足不等式/sn-n-6/
已知数列{an}满足3an+1+an=4,a1=9,前n项和为sn,则满足不等式/sn-n-6/