tan(π/4-α)=-1/3 则sin(2α+π/4)的值为?
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tan(π/4-α)=-1/3则sin(2α+π/4)的值为?tan(π/4-α)=-1/3则sin(2α+π/4)的值为?tan(π/4-α)=-1/3则sin(2α+π/4)的值为?∵tan(
tan(π/4-α)=-1/3 则sin(2α+π/4)的值为?
tan(π/4-α)=-1/3 则sin(2α+π/4)的值为?
tan(π/4-α)=-1/3 则sin(2α+π/4)的值为?
∵tan(¼π-α)=(1-tanα)/(1+tanα)=-1/3,∴tanα=2,
∴sin2α=2tanα/(1+tan²α)=4/5,
cos2α=(1-tan²α)/(1+tan²α)=-3/5,
∴sin(2α+¼π)=½√2(sin2α+cos2α)=√2/10.
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tan(π/4-α)=-1/3 则sin(2α+π/4)的值
tan(π/4-α)=-1/3 则sin(2α+π/4)的值为?
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