若tanα=1/3则sin^2α-sinαcosα-cos^2α=

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若tanα=1/3则sin^2α-sinαcosα-cos^2α=若tanα=1/3则sin^2α-sinαcosα-cos^2α=若tanα=1/3则sin^2α-sinαcosα-cos^2α=s

若tanα=1/3则sin^2α-sinαcosα-cos^2α=
若tanα=1/3则sin^2α-sinαcosα-cos^2α=

若tanα=1/3则sin^2α-sinαcosα-cos^2α=
sin^2α-sinαcosα-cos^2α
=(sin^2α-sinαcosα-cos^2α)/(sin²a+cos²a)
=(tan²a-tana-1)/(tan²a+1) 分子分母同时除以cos²a
=(1/9-1/3-1)/(1/9+1)
=-11/10

tanα=1/3,sinα和cosα同正负
所以3sinα=cosα,9sin^2α=cos^2α,sin^2a=1/10,cos^2α=9/10
所以sinαcosa=3/10
所以sin^2α-sinαcosα-cos^2α=-11/10