π－arctan(3/2)－arctan(2/3)=?

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π－arctan(3/2)－arctan(2/3)=?π－arctan(3/2)－arctan(2/3)=?π－arctan(3/2)－arctan(2/3)=?设arctan(3/2)=A,arct

π－arctan(3/2)－arctan(2/3)=?
π－arctan(3/2)－arctan(2/3)=?

π－arctan(3/2)－arctan(2/3)=?
设arctan(3/2)=A,arctan(2/3)=B
所以tanA=3/2>0,tanB=2/3>0
又因为A,B属于[-π/2,π/2]
所以A,B都为锐角
tanA*tanB=1,故A和B互余
A+B=π/2
π－arctan(3/2)－arctan(2/3)=π/2

记x=arctan(3+2√2)，y=arccos[(√6)/3] cosy=√6/3 siny=√3/3 tany=siny/cosy=√2/2 tanx=3+2√2 tan(x-y)=(tanx-tany)/(1+tanxtany)=(3+2√2-√2/2)/(1+(3+2√2)(√2/2))=1 所以arctan(3+2√2)-arccos[(√6)/3]=x-y=π/4
很不错哦，...

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记x=arctan(3+2√2)，y=arccos[(√6)/3] cosy=√6/3 siny=√3/3 tany=siny/cosy=√2/2 tanx=3+2√2 tan(x-y)=(tanx-tany)/(1+tanxtany)=(3+2√2-√2/2)/(1+(3+2√2)(√2/2))=1 所以arctan(3+2√2)-arccos[(√6)/3]=x-y=π/4
很不错哦，你可以试下
o铅┿o铅┿w唯mЖzb℃夕gx┯（x┯（y44862223052011-9-11 13:05:57

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π－arctan(3/2)－arctan(2/3)=? arctan(-2)+arctan(-3)=? arctanπ/2＝? arctan 用复变函数证明arctan (1/2) + arctan (1/3) =π/4 arctan(1/3)+arctan(1/2)的值为? 级数求和：arctan(1/2)+arctan(1/2^2)+arctan(1/2^3)+...+arctan(1/2^n)+... 求证：arctan 1/2+arctan 1/5+arctan 1/8=π/4 cos[arctan(1/2) - arctan(-2)]=? X－sinx/arctan^3(x)求极限 5.lim(e^x^2) －1/arctan x-0 cos(2arctan√2+π/3)的值为 求值：sin[1/2arctan(-4/3)] arctan(x^2 - 3)定义域是? 计算cos(1/2arctan(-3/4)) 求值 arctan根号3 arctan√3 arctan根号2是什么,