[1 log(9544.5) log(0.84) log(34403.8) log(255);1 log(7183) log(0.31) log(5269) log(435);1 log(11144) log(0.06) log(4299) log(770);1 log(6618) log(0.12) log(16468) log(963);1 log(6353) log(0.07) log(2050) log(1473)]求以上矩阵逆矩阵,麻烦给

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[1log(9544.5)log(0.84)log(34403.8)log(255);1log(7183)log(0.31)log(5269)log(435);1log(11144)log(0.06)

[1 log(9544.5) log(0.84) log(34403.8) log(255);1 log(7183) log(0.31) log(5269) log(435);1 log(11144) log(0.06) log(4299) log(770);1 log(6618) log(0.12) log(16468) log(963);1 log(6353) log(0.07) log(2050) log(1473)]求以上矩阵逆矩阵,麻烦给
[1 log(9544.5) log(0.84) log(34403.8) log(255);
1 log(7183) log(0.31) log(5269) log(435);
1 log(11144) log(0.06) log(4299) log(770);
1 log(6618) log(0.12) log(16468) log(963);
1 log(6353) log(0.07) log(2050) log(1473)]
求以上矩阵逆矩阵,麻烦给出代码和结果,

[1 log(9544.5) log(0.84) log(34403.8) log(255);1 log(7183) log(0.31) log(5269) log(435);1 log(11144) log(0.06) log(4299) log(770);1 log(6618) log(0.12) log(16468) log(963);1 log(6353) log(0.07) log(2050) log(1473)]求以上矩阵逆矩阵,麻烦给
>> A=[1 log(9544.5) log(0.84) log(34403.8) log(255);
1 log(7183) log(0.31) log(5269) log(435);
1 log(11144) log(0.06) log(4299) log(770);
1 log(6618) log(0.12) log(16468) log(963);
1 log(6353) log(0.07) log(2050) log(1473)]
A =
1.0000 9.1637 -0.1744 10.4459 5.5413
1.0000 8.8795 -1.1712 8.5696 6.0753
1.0000 9.3187 -2.8134 8.3661 6.6464
1.0000 8.7975 -2.1203 9.7092 6.8701
1.0000 8.7567 -2.6593 7.6256 7.2951
>> inv(A)
ans =
-31.4194 46.8239 -4.4548 19.2384 -29.1880
2.4750 -3.2546 0.8564 -2.1800 2.1032
1.2969 -1.1946 -0.6057 -0.9990 1.5024
-0.0124 -0.1882 0.0080 0.5792 -0.3866
1.8218 -2.7506 -0.6466 -0.9900 2.5654
B=[log(3093);
log(1489);
log(367);
log(1631);
log(218)]
B =
8.0369
7.3059
5.9054
7.3969
5.3845
>> X=inv(A)*B
X =
48.4093
-3.6296
-1.1812
0.7752
-2.7818

a=[1 log(9544.5) log(0.84) log(34403.8) log(255);
1 log(7183) log(0.31) log(5269) log(435);
1 log(11144) log(0.06) log(4299) log(770);
1 log(6618) log(0.12) log(16468) log(963);
1 log(...

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a=[1 log(9544.5) log(0.84) log(34403.8) log(255);
1 log(7183) log(0.31) log(5269) log(435);
1 log(11144) log(0.06) log(4299) log(770);
1 log(6618) log(0.12) log(16468) log(963);
1 log(6353) log(0.07) log(2050) log(1473)]
a =
1.0000 9.1637 -0.1744 10.4459 5.5413
1.0000 8.8795 -1.1712 8.5696 6.0753
1.0000 9.3187 -2.8134 8.3661 6.6464
1.0000 8.7975 -2.1203 9.7092 6.8701
1.0000 8.7567 -2.6593 7.6256 7.2951
>> inv(a)
ans =
-31.4194 46.8239 -4.4548 19.2384 -29.1880
2.4750 -3.2546 0.8564 -2.1800 2.1032
1.2969 -1.1946 -0.6057 -0.9990 1.5024
-0.0124 -0.1882 0.0080 0.5792 -0.3866
1.8218 -2.7506 -0.6466 -0.9900 2.5654

收起

a=[1 log(9544.5) log(0.84) log(34403.8) log(255);
1 log(7183) log(0.31) log(5269) log(435);
1 log(11144) log(0.06) log(4299) log(770);
1 log(6618) log(0.12) log(16468) log(963);
1 log(6353) log(0.07) log(2050) log(1473)];
inv(a)

[1 log(9544.5) log(0.84) log(34403.8) log(255);1 log(7183) log(0.31) log(5269) log(435);1 log(11144) log(0.06) log(4299) log(770);1 log(6618) log(0.12) log(16468) log(963);1 log(6353) log(0.07) log(2050) log(1473)]求以上矩阵逆矩阵,麻烦给 log log log 64^1/3-(-2/3)^0+log(2)8+(log(8)9)/(log(2)3) 证明：log(A)M=log(b)M/log(b)A (b>0且b≠1）. log底数7[log底数3（log底数2X）]=0,那么x^1/2的值是 27-1/ 若a>0,b>0,a*b>1,log(1/2)[a]=ln2,则log(a)[b]与log(1/2)[a]的关系是：（）?(A)log(a)b< log(1/2)[a](B)log(a)b= log(1/2)[a](C)log(a)b>log(1/2)[a](D)log(a)b与log(1/2)[a] 无法比较大小我做到一半就做不下去了：a=(1/2)^(ln2)log log(1/2) |x-1|>0 log(x)(100)-lgx+1=0 log(1/8)X log(9)x+log(x^2)3=1的解为?原方程可可化为log(3 ²)x+log(x)²3=1 ,∴1/2*log(3)X+1/2*log(x)3=1,∴[log(3)x]²-2log(x)3+1=0,即[log(3)x-1]²=0请问这里的[log(3)x]²-2log(x)3+1=0是怎么推出来的,刚学基础不好, log(a-1) (2x-1)-log(a-1)(x-1)>0 解[log(x-1)]²+2log(x-1)-3=0 若f(x)=log a (1-x),g(x)=log a (1+x) 0 已知函数f(x)=log.(1-x)+log.(x+3)（0 已知log(8)[log(3)X]=0,那么X^(-1/2)= 求下式x值log₂（1og₃（log底数5x））=0