log 1/2 ｛sin(π/3-πx/4)｝的递增区间

用C语言计算log(5)log(3)-log(2))/sin(π/3)=#include #includeint main(){int a=5,b=3,c=2;double y;y=(log(a)log(b)-log(c))/sin(π/b);printf((log(5)log(3)-log(2))/sin(π/3)=%ld,y);return 0;}x这哪里错了? log 1/2 ｛sin(π/3-πx/4)｝的递增区间 log((sin(30)*2)-3+π是多少 log((sin(30))*2)-3+π log((sin(30))*2)-3+π y=3^x+log以2为底的x+sin(π/4)求导, 求f(x)=log(1/2)sin(x-π/4)的单调递减区间 函数y=log(1/2)(sin(2x+π/4))的定义域为?如题 函数y=log(1/2)(sin(2x+π))的定义域为多少 求函数y=log 1/2 sin(2x+π/4)的单调区间 函数y=log 0.5(3sinπx+1)的值域为 f(x)=sin(2x+3/π）,求g(x)=log1/2(1/2在log的下面）f(x)的单调区间 求y=log下标(1/3)sin(x+π/4)的单调增区间求y=log下标(1/3)[sin(x+π/4)]的单调增区间 y=log底数是2 sin(-2x+三分之π)+1的单调增区间 y=log以a为底sin(2x-π/3)的对数 它的单调区间? 设a＞0且a≠1,试讨论函数y=log a sin(2x-π/3）的单调区间 (1)已知sin(π-x)=log以8为底1/4的对数,且x∈(-π/2,0),则cos(π+x)的值? log(tanθ+cotθ)sinθ=-1/4,θ∈(0,π／2),则log(tanθ)sinθ=?需要过程.谢谢.