lim(1+2n+3n^2+……+2004n^2003)/(n^2003+2n^2002+……+2003n+2004)
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lim(1+2n+3n^2+……+2004n^2003)/(n^2003+2n^2002+……+2003n+2004)lim(1+2n+3n^2+……+2004n^2003)/(n^2003+2n^2
lim(1+2n+3n^2+……+2004n^2003)/(n^2003+2n^2002+……+2003n+2004)
lim(1+2n+3n^2+……+2004n^2003)/(n^2003+2n^2002+……+2003n+2004)
lim(1+2n+3n^2+……+2004n^2003)/(n^2003+2n^2002+……+2003n+2004)
当N趋向0时,答案为1/2004
当N趋向无穷时,可忽略分子分母中的低次幂,看高次幂系数(洛必达法则推论),答案为2004
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