y=2x^2-4x-8 y=0.5x^2+2x-1
来源:学生作业帮助网 编辑:六六作业网 时间:2024/12/26 16:29:48
y=2x^2-4x-8y=0.5x^2+2x-1y=2x^2-4x-8y=0.5x^2+2x-1y=2x^2-4x-8y=0.5x^2+2x-1y=2x^2-4x-8=2(x²-2x)-8=
y=2x^2-4x-8 y=0.5x^2+2x-1
y=2x^2-4x-8 y=0.5x^2+2x-1
y=2x^2-4x-8 y=0.5x^2+2x-1
y=2x^2-4x-8
=2(x²-2x)-8
=2(x-1)²-10
y=0.5x^2+2x-1
=0.5(x²+4x)-1
=0.5(x+2)²-3
x-y/x-x+y/y-(x+y)(x-y)/y² y/x=2
(x-y) (x-2y)+(x+2y) (x-3y)-2(x-3y) (x-4y)=
[(x+2y)(x-2y)-(x-2y)^2+8y(x+y)]除以4x=
(x-4y)(2x+y)=
4x方y/(x-2y)(x+2y)怎么算[x方/x-2y]-4x方y/(x-2y)(x+2y)=?
【2(x-y)^3-8(x-y)^2(x+y)+6y(x-y)^2】/2(x-y)^2=
[(2x-y)^2-y(y-4x)-8x]其中x=-1/2
y=2x^2-4x-8 y=0.5x^2+2x-1
9y=3x-(x-1),4(x+y)-(2x+4)=8y
[(2x+y)²-y(y+4x)-8x】/4x,其中x=-1,y=2005 急
(4x-2y-z)-{5x[8y-2y-(x+y)]-x+(3y-10z)]=? kuaihuajian
若x-y=1 化简(x+y)(x^2+y^2)(x^4+y^4)(x^8+y^8)(x^16+y^16)
已知实数x.y满足根号(x+y-8)+根号(8-x-y)=根号(3x-y-4)+根号(x-2y+7),求x,y
(x+y)^2(x-y)^2(x^4+x^2y^2+y^4)=?
3(x+y)+2(x-y)=36 4(x+y)-5(x-y)=2
(x+y)/2- x-y/2=6 3(x+y)=4(x-y)
x+y/3+x-y/2=6 4(x+y)-2(x-y)=40
x*x+2x+y*y-4y+5=0 x= y=