求高数极限,明天要考试了,π/n乘以(cos^2π/n+cos^22π/n……cos(n-1)π/n),当n趋向与无穷时的极限!

来源:学生作业帮助网 编辑:六六作业网 时间:2024/11/26 00:50:50
求高数极限,明天要考试了,π/n乘以(cos^2π/n+cos^22π/n……cos(n-1)π/n),当n趋向与无穷时的极限!求高数极限,明天要考试了,π/n乘以(cos^2π/n+cos^22π/

求高数极限,明天要考试了,π/n乘以(cos^2π/n+cos^22π/n……cos(n-1)π/n),当n趋向与无穷时的极限!
求高数极限,明天要考试了,
π/n乘以(cos^2π/n+cos^22π/n……cos(n-1)π/n),当n趋向与无穷时的极限!

求高数极限,明天要考试了,π/n乘以(cos^2π/n+cos^22π/n……cos(n-1)π/n),当n趋向与无穷时的极限!