f(x)=根号2*sin(2x+π/4)求x属于【-π/2,π/2】的单调增区间

来源:学生作业帮助网 编辑:六六作业网 时间:2024/11/25 13:25:38
f(x)=根号2*sin(2x+π/4)求x属于【-π/2,π/2】的单调增区间f(x)=根号2*sin(2x+π/4)求x属于【-π/2,π/2】的单调增区间f(x)=根号2*sin(2x+π/4)

f(x)=根号2*sin(2x+π/4)求x属于【-π/2,π/2】的单调增区间
f(x)=根号2*sin(2x+π/4)求x属于【-π/2,π/2】的单调增区间

f(x)=根号2*sin(2x+π/4)求x属于【-π/2,π/2】的单调增区间
函数f(x)=根号2*sin(2x+π/4)单调增区间为:
2kπ-π/2≤2x+π/4≤2kπ+π/2
化简得:kπ-3π/8≤x≤kπ+π/8
因为x属于【-π/2,π/2】
所以k=0,-3π/8≤x≤π/8
即函数单调增区间为[-3π/8,π/8]