(√ 2 sinx )-sin(x-π/4) 化简如题
来源:学生作业帮助网 编辑:六六作业网 时间:2024/12/25 14:27:58
(√2sinx)-sin(x-π/4)化简如题(√2sinx)-sin(x-π/4)化简如题(√2sinx)-sin(x-π/4)化简如题原式=√2sinx-sinxcosπ/4+cosxsinπ/4
(√ 2 sinx )-sin(x-π/4) 化简如题
(√ 2 sinx )-sin(x-π/4) 化简
如题
(√ 2 sinx )-sin(x-π/4) 化简如题
原式=√2sinx-sinxcosπ/4+cosxsinπ/4
=√2sinx-sinx*√2/2+cosxsinπ/4
=sinx*√2/2+cosxsinπ/4
=sinxcos π/4+cosxsinπ/4
=sin(x+π/4)
(√ 2 sinx )-sin(x-π/4) 化简如题
|sin(x+π/2)|-|sinx|求导过程?
sinx>sin(2π/3-x)(0
(sinx-1)tanx怎么化简成[(sinx-sinπ/2)/sin(x+π/2)]sinx,x趋于π/2
化简变形f(x)=[2sin(x+π/3)+sinx]cosx-√3sin^2x
f(x)=2sinx*sin(x+π/3) 化简
求X解集:sinx=2sin(π/3-x)
函数y=sin(π/2-x)+sinx的最大值为什么cosx+sinx=√2sin(x+π /4)为什么?
证明三角不等式设x属于(0,π/2),求证:sin√x<√sinx
函数f(x)=√(3)sinx+sin(π/2+x)的最大值是?
怎样使f(x)=sinx+cosx=√2*sin(x+π/4)
√3sinx+cosx=2(√3/2sinx+cosx/2)为什么等于2sin(x+π/6)
确定函数f(x)=lg(sinx+根号1+sin^2x)的奇偶性?f(-x)=lg[-sinx+√(1+sin²x)]=lg{[-sin²+(1+sin²x)]/[sinx+√(1+sin²x)]}这步是为什么?
f(x)=lg(sinx+根号下(1+sin^2x).f(-x)=lg[-sinx+√(1+sin²x)]=lg{[-sin²+(1+sin²x)]/[sinx+√(1+sin²x)]}这步是为什么?
2sina(x-π/4)sin(x+π/4) 怎么转换成(sinx-cosx)(sinx+cosx)?
已知函数y=-sin^2x+sinx(-π/2
sinx变为sin(2x+π/2)怎么变?
证明x∈(0,π/2),cos(cosx)>sin(sinx)