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已知0已知0已知0cos(45°+a)=sin[90°-(45°+a)]=sin(45°-a)=1/3sin(45°-α)=1/3那么cos(45°+α)=cos[90°-(45°-α)]=sin(4

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已知0<α<45°,sin(45°-α)=1/3,则cos(45°+α)=?

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cos(45°+a)
=sin[90°-(45°+a)]
=sin(45°-a)
=1/3

sin(45°-α)=1/3
那么cos(45°+α)=cos[90°-(45°-α)]=sin(45°-α)=1/3

cos(45°+α)=sin(90°-(45°+α))=sin(45°-α)=1/3