已知数列an的通项公式为an=3n-50,求其前n项和Sn的最小值
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已知数列an的通项公式为an=3n-50,求其前n项和Sn的最小值
已知数列an的通项公式为an=3n-50,求其前n项和Sn的最小值
已知数列an的通项公式为an=3n-50,求其前n项和Sn的最小值
an=3n-50,
a1=-47
d=3
a17=1>0
a16=-2<0
n=16,Sn取最小值:
s16=16*(-47)+16*15*3/2
=-392
an=3n-50=3(n-1)-47
首项a1=-47,公差d=3
前n项和Sn=na1+n(n-1)d/2=3/2n平方-97/2n
当n=-(197/2)/(3/2)=97/3时,sn最大
但是n必为整数,n=32时,sn=-16,
n=33时,sn=33
因此,n=33时,sn最大,为33
a(n) = 3n-50, n = 1,2,...
S(n) = a(1) + a(2) + ... + a(n)
= 3*1 - 50 + 3*2 - 50 + ... + 3*n - 50
= 3[1 + 2 + ... + n] - 50n
= 3n(n+1)/2 - 50n
= 3n^2/2 - 97n/2
= 3/2[n^2 -...
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a(n) = 3n-50, n = 1,2,...
S(n) = a(1) + a(2) + ... + a(n)
= 3*1 - 50 + 3*2 - 50 + ... + 3*n - 50
= 3[1 + 2 + ... + n] - 50n
= 3n(n+1)/2 - 50n
= 3n^2/2 - 97n/2
= 3/2[n^2 - 97n/3 + (97/6)^2] - 3/2(97/6)^2
= 3/2[n - 97/6]^2 - 97^2/24.
96/6 = 16 < 97/6 < 102/6 = 17
S(16) = 3/2[1/6]^2 - 97^2/24,
S(17) = 3/2[5/6]^2 - 97^2/24 > S(16)
所以,S(n)的最小值=S(16) = 3/2[1/6]^2 - 97^2/24 = 1/24 - 97^2/24 = -96*98/24 = -392
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