lim(an^2/(3n+1)-n)=b a+b=?

来源:学生作业帮助网 编辑:六六作业网 时间:2024/12/22 17:56:13
lim(an^2/(3n+1)-n)=ba+b=?lim(an^2/(3n+1)-n)=ba+b=?lim(an^2/(3n+1)-n)=ba+b=?你好!lim[an²/(3n+1)-n]

lim(an^2/(3n+1)-n)=b a+b=?
lim(an^2/(3n+1)-n)=b a+b=?

lim(an^2/(3n+1)-n)=b a+b=?
你好!
lim [an²/(3n+1) - n]
= lim [an² - n(3n+1)]/(3n+1)
= lim [(a-3)n² - n] / (3n+1)
极限存在,必有a-3=0即a=3
极限为 -1/3 即 b = -1/3
故 a+b = 8/3

=0, arctanx--pai/2,x--无穷大 lim (arctan x)/x x→∞ = (½π)/∞ = 0 x趋向无穷大时 1/x是无穷小量,而arctanx是有

0

什么意思