x^2y--[-x^2y-(2XYZ-X^2Z-3x^2y)-4x^2z]-XYZ其中x=-3,y=2,z=-1x^2y--[-x^2y-(2XYZ-X^2Z-3x^2y)-4x^2z]-XYZ其中x=-3,y=2,z=-1
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x^2y--[-x^2y-(2XYZ-X^2Z-3x^2y)-4x^2z]-XYZ其中x=-3,y=2,z=-1x^2y--[-x^2y-(2XYZ-X^2Z-3x^2y)-4x^2z]-XYZ其中x
x^2y--[-x^2y-(2XYZ-X^2Z-3x^2y)-4x^2z]-XYZ其中x=-3,y=2,z=-1x^2y--[-x^2y-(2XYZ-X^2Z-3x^2y)-4x^2z]-XYZ其中x=-3,y=2,z=-1
x^2y--[-x^2y-(2XYZ-X^2Z-3x^2y)-4x^2z]-XYZ其中x=-3,y=2,z=-1
x^2y--[-x^2y-(2XYZ-X^2Z-3x^2y)-4x^2z]-XYZ其中x=-3,y=2,z=-1
x^2y--[-x^2y-(2XYZ-X^2Z-3x^2y)-4x^2z]-XYZ其中x=-3,y=2,z=-1x^2y--[-x^2y-(2XYZ-X^2Z-3x^2y)-4x^2z]-XYZ其中x=-3,y=2,z=-1
应该没算错吧,好久不做运算啦~
2x+3y+4z,xyz
正数XYZ满足(X+Y)(X+Z)=2则XYZ(X+Y+Z)最大值
x^3+x^2y-x^z-xyz分解因式
3x^2y-{xyz-(2xyz-x^2z)-4x^2z+[3x^2y-(4xyz-5x^z-3xyz)]}化简
化简求值(2x^3-xyz)-2(x^3-y^3+xyz)+(xyz-2y^3)=?
24xy^2z^2(x+y+z)-32xyz(z-x-y)^2+8xyz^3(z-x-y)
24xy^2z^2(x+y+z)-32xyz(z-x-y)^2+8xyz^3(z-x-y)
因式分解 (x+y+z)^2+yz(y+z)+xyz
x+y+z+2=xyz,x,y,z.为正实数,证明:xyz(x-1)(y-1)(z-1)
(x*x+2)(y*y+4)(z*z+8)=64xyz,求x,y,z
x²y-y²z+z²x-x²z+y²x+z²y-2xyz
先化简再求值3xyz+2(x^2y+y^2z-xyz)-xyz+2z^2x x=1 y= -1 z=2
(2x^3-xyz)-2(x^3-y^3+xyz)+(xyz-2y^3),其中x=-1,y=-2,z=-3.
化简求值:(2x³-xyz)-2(x³-y³+xyz)+(xyz-2y³),x=1,y=2,z=-3
先化简,再求值:3xyz+2(x²y+y²z-xyz)-xyz+2z²x,其中x=1、y=-1、z=2;
(2x³-xyz)-2(x³-y³+xyz)+(xyz-3y³) x=1 y=-2 z=-3
x^2y--[-x^2y-(2XYZ-X^2Z-3x^2y)-4x^2z]-XYZ其中x=-3,y=2,z=-1x^2y--[-x^2y-(2XYZ-X^2Z-3x^2y)-4x^2z]-XYZ其中x=-3,y=2,z=-1
已知xyz适合关系式√3x+y-z-2+√2x+y-z=√x+y-2011+2011-x-y,试求xyz的值