x^2 1/x^2-3-3/3x=0

一个“整式的乘法”的问题请先阅读下列解题过程,再仿做下面的问题.已知X*X+X-1=0,求X*X*X+2*X*X+3的值.解X*X*X+2X*X+3=X*X*X+X*X-X+X*X+X+3=X{X*X

x^4+x^3+x^2+x+1=0,x^2006+x^2005+x^2004+x^2003+x^2002x^4+x^3+x^2+x+1=0,x^2006+x^2005+x^2004+x^2003+x^

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(X+1)X(X+2)X(X+3)=504(X+1)X(X+2)X(X+3)=504(X+1)X(X+2)X(X+3)=504等价于x^3+6x^2+11x-498=0令左边等于y试根x=6时y=0做

七年级下册政治复习提纲(山东人民出版社)第五单元是青春的脚步青春的气息别弄错了啊!格式：XXXXXXXXX1、XXXXXXXXXX.2、XXXXXXXXX.3、XXXXXXXXXXX.七年级下册政治复

(x+2)(x-3)(x-6)(x-1)=0(x+2)(x-3)(x-6)(x-1)=0(x+2)(x-3)(x-6)(x-1)=0有种方法叫做穿针引线法,需要在纸上画出函数的简图,这个题的答案应该是

已知1+x+x^2+x^3=0,求x+x^2+x^3+x^4+x^+x^6+x^7+x^8的值已知1+x+x^2+x^3=0,求x+x^2+x^3+x^4+x^+x^6+x^7+x^8的值已知1+x+

如果1+x+x^2+x^3=0,求x+x^2+X^3+x^4+x^5+x^6+x^7+x^8的值,如果1+x+x^2+x^3=0,求x+x^2+X^3+x^4+x^5+x^6+x^7+x^8的值,如果

1/(x*x-2x-3)+2/(x*-x-6)+3/(x*x+3x+2)=01/(x*x-2x-3)+2/(x*-x-6)+3/(x*x+3x+2)=01/(x*x-2x-3)+2/(x*-x-6)+

X^2-3X-2=0,求(x-2x-1/x)÷(x-1)/(x^2-2x)X^2-3X-2=0,求(x-2x-1/x)÷(x-1)/(x^2-2x)X^2-3X-2=0,求(x-2x-1/x)÷(x-

已知X^2-X-1=0,则-X^3+2X+2006X^*X为什么=X^2+X已知X^2-X-1=0,则-X^3+2X+2006X^*X为什么=X^2+X已知X^2-X-1=0,则-X^3+2X+200

已知x^-x-1=0,求x^4+x^3-x^2-4x+3已知x^-x-1=0,求x^4+x^3-x^2-4x+3已知x^-x-1=0,求x^4+x^3-x^2-4x+3x^4+x^3-x^2-4x+3

已知x*x-3x+1=0求√(x*x+1/x-2)=?已知x*x-3x+1=0求√(x*x+1/x-2)=?已知x*x-3x+1=0求√(x*x+1/x-2)=?x*x-3x+1=0x*x+1=3x√

(x-3/x-2)-(x-2/x-1)=(x-5/x4)-(x-4/x-3)(x-3/x-2)-(x-2/x-1)=(x-5/x4)-(x-4/x-3)(x-3/x-2)-(x-2/x-1)=(x-5

解方程x/(x-2)=2x/(x-3)+(1-x)/(x-5x+6)解方程x/(x-2)=2x/(x-3)+(1-x)/(x-5x+6)解方程x/(x-2)=2x/(x-3)+(1-x)/(x-5x+

x(x-2)-2x(x+1)-3x(x-5)其中x=负½x(x-2)-2x(x+1)-3x(x-5)其中x=负½x(x-2)-2x(x+1)-3x(x-5)其中x=负½x

x(x+1)+(x+2)+(x+3)+(x+4)+(x+5)=27求xx(x+1)+(x+2)+(x+3)+(x+4)+(x+5)=27求xx(x+1)+(x+2)+(x+3)+(x+4)+(x+5)

请问这道题咋做：（x）X(x+1)X(x+2)X(x+3)=360请问这道题咋做：（x）X(x+1)X(x+2)X(x+3)=360请问这道题咋做：（x）X(x+1)X(x+2)X(x+3)=360x

X+X+X+(X-1)+(X-2)+(X-3)+(X-4)=10(X-3)+(X-4)X+X+X+(X-1)+(X-2)+(X-3)+(X-4)=10(X-3)+(X-4)X+X+X+(X-1)+(X