limn趋向于无穷大(2∧n)sin(x/2∧n)

limn^2(1-cosπ/n),n趋向无穷大limn^2(1-cosπ/n),n趋向无穷大limn^2(1-cosπ/n),n趋向无穷大原式=lim(1-cosπ/n)/(1/n^2),n趋向无穷大

limn趋向无穷大(2^(n+1)-3^n)/(3^(n+1)+2^n)=?limn趋向无穷大(2^(n+1)-3^n)/(3^(n+1)+2^n)=?limn趋向无穷大(2^(n+1)-3^n)/(

数列极限定义证明limn^(2/3)sinn/(n+1)=0,n趋向于无穷大,马上求解数列极限定义证明limn^(2/3)sinn/(n+1)=0,n趋向于无穷大,马上求解数列极限定义证明limn^(

求下列极限.lim(n趋向于无穷大)(2x次方)*(sin*1/2x次方)求下列极限.lim(n趋向于无穷大)(2x次方)*(sin*1/2x次方)求下列极限.lim(n趋向于无穷大)(2x次方)*(

limn趋向正无穷大.n-1/2n+1的极限是limn趋向正无穷大.n-1/2n+1的极限是limn趋向正无穷大.n-1/2n+1的极限是lim(n-1)/(2n+1)上下同除以n=lim(1-(1/

求极限(n+4/n+3)∧2n.n趋向于无穷大求极限(n+4/n+3)∧2n.n趋向于无穷大求极限(n+4/n+3)∧2n.n趋向于无穷大=lim[1+1/(n+3)]^2n=lim[1+1/(n+3

求lim2^n*sin(x/2^n)其中n趋向无穷大求lim2^n*sin(x/2^n)其中n趋向无穷大求lim2^n*sin(x/2^n)其中n趋向无穷大提示：利用sinx/x当x->0时极限为1.

limn趋向于无穷（n+3/n+1）^n/2=?limn趋向于无穷（n+3/n+1）^n/2=?limn趋向于无穷（n+3/n+1）^n/2=?你问的是哪一个?我按我的理解写了两个等于1，，n趋于无穷

lim(1+1/2n)^nn趋向于无穷大lim(1+1/2n)^nn趋向于无穷大lim(1+1/2n)^nn趋向于无穷大看你喜不喜欢洛必达了可以利用重要极限limn->∞(1+1/n)^n=e令t=2

当n趋向无穷大时,1/n乘于sin(1/n)等价于1/(n^2)吗?当n趋向无穷大时,1/n乘于sin(1/n)等价于1/(n^2)吗?当n趋向无穷大时,1/n乘于sin(1/n)等价于1/(n^2)

当n趋向于无穷大时,n{sin(1/n)-sin[1/(n+1)]}趋向当n趋向于无穷大时,n{sin(1/n)-sin[1/(n+1)]}趋向当n趋向于无穷大时,n{sin(1/n)-sin[1/(

高等数学（工专）求极限问题求下列极限①当x无线趋近于0时tan5x/x的极限②当n趋向于无穷大时,2^n*sin(x/2^n)的极限③当n趋向于无穷大时(（2n+3）/(2n+1))^(n+1)的极限

lim√1+1/n^2n趋向于无穷大lim√1+1/n^2n趋向于无穷大lim√1+1/n^2n趋向于无穷大=1因为1/n²趋向于零

请教一个极限题,lim（n趋向于无穷大）2的n次方乘以sin（x比2的n次方）等于多少啊?请教一个极限题,lim（n趋向于无穷大）2的n次方乘以sin（x比2的n次方）等于多少啊?请教一个极限题,li

n趋向于无穷大时,极限LIM(n^2)sin^2(Θ/n)=-(Θ^2)/2求具体过程.n趋向于无穷大时,极限LIM(n^2)sin^2(Θ/n)=-(Θ^2)/2求具体过程.n趋向于无穷大时,极限L

讨论级数sin(nπ/4)/n^2n从1趋向于无穷大的绝对收敛性与条件收敛性讨论级数sin(nπ/4)/n^2n从1趋向于无穷大的绝对收敛性与条件收敛性讨论级数sin(nπ/4)/n^2n从1趋向于无

紧急：求limn*sin(π(n^2+2)^0.5）*(-1)^n,n趋向无穷大；紧急：求limn*sin(π(n^2+2)^0.5）*(-1)^n,n趋向无穷大；紧急：求limn*sin(π(n^2

limnsin(3x/n)=?n趋向于无穷大limnsin(3x/n)=?n趋向于无穷大limnsin(3x/n)=?n趋向于无穷大sin(3x/n)lim-----------*lim(3x)=1*

当N趋向于无穷大2/N^2+...+2N/N^2的极限当N趋向于无穷大2/N^2+...+2N/N^2的极限当N趋向于无穷大2/N^2+...+2N/N^2的极限求和为(2+4+..+2n)/n^2=

lim(n趋向于无穷大)(5n平方+n-2)/(3n平方-2)lim(n趋向于无穷大)(5n平方+n-2)/(3n平方-2)lim(n趋向于无穷大)(5n平方+n-2)/(3n平方-2)lim(n趋向