满足an+2snsn-1=0A1=1/2

已知数列an的前n项和Sn满足an+2SnSn-1=0(n>=2),a1=1/2,求an已知数列an的前n项和Sn满足an+2SnSn-1=0(n>=2),a1=1/2,求an已知数列an的前n项和S

已知在数列{an}的前n项和Sn满足an+2SnSn-1=0(n大于2）,a1=二分之一,求an已知在数列{an}的前n项和Sn满足an+2SnSn-1=0(n大于2）,a1=二分之一,求an已知在数

已知数列的前n项和Sn满足an+2SnSn-1=0(n大于等于2)a1=1/2,n-1是下角标求an已知数列的前n项和Sn满足an+2SnSn-1=0(n大于等于2)a1=1/2,n-1是下角标求an

已知数列{an}的前n项和Sn,且满足an+2SnSn-1=0(n2),a1=1/2.求Tn=s1s2+s2s3+...+sns已知数列{an}的前n项和Sn,且满足an+2SnSn-1=0(n2),

数列an中已知a1=3,且2an=SnSn-1,求通项公式an数列an中已知a1=3,且2an=SnSn-1,求通项公式an数列an中已知a1=3,且2an=SnSn-1,求通项公式an因为2an=S

已知数列AN的前N项和SN=A1+A2+A3+……+AN满足AN+2SNSN-1=0(N大于等于2)a1=1/2,求AN已知数列AN的前N项和SN=A1+A2+A3+……+AN满足AN+2SNSN-1

若an+2SnSn-1=0,a1=0.5(1)求证{1/Sn}是等差数列(2)求an若an+2SnSn-1=0,a1=0.5(1)求证{1/Sn}是等差数列(2)求an若an+2SnSn-1=0,a1

已知数列AN的前N项和SN=A1+A2+A3+……+AN满足AN+2SNSN-1=0(N大于等于2)a1=1/2.已知数列AN的前N项和SN=A1+A2+A3+……+AN满足AN+2SNSN-1=0(

已知数列an的前n项和为Sn,且满足a1=1/2,An=-2SnSn-1n>=2已知数列an的前n项和为Sn,且满足a1=1/2,An=-2SnSn-1n>=2已知数列an的前n项和为Sn,且满足a1

a1=1an=-SnSn-1（n>=2)求Sna1=1an=-SnSn-1（n>=2)求Sna1=1an=-SnSn-1（n>=2)求Snan=sn-s(n-1)=-sn*s(n-1)因为Sn不等于0

1、已知数列｛an｝的前几项的和为sn,且满足a1=,an=-2snsn-1（n≥2）1、已知数列｛an｝的前几项的和为sn,且满足a1=1/2,an=-2snsn-1（n≥2）数列｛an｝是否为等差

数列{an}中前n项和为sn且a1=2,snsn-1=an,求an数列{an}中前n项和为sn且a1=2,snsn-1=an,求an数列{an}中前n项和为sn且a1=2,snsn-1=an,求an当

数列an的前n项和sn满足an+2snsn-1=0(n>=2)且a1=1/21、求证数列1/sn为等差数列2、求通项an数列an的前n项和sn满足an+2snsn-1=0(n>=2)且a1=1/21、

已知数列{an}的前n项和为sn,且满足a1=1/2,an+2snsn-1=0(n≥2)(1)问:数列{1/Sn}是否为等差数列?(2)求Sn和an已知数列{an}的前n项和为sn,且满足a1=1/2

已知数列｛an｝的前n项和为Sn,且满足an+2SnSn-1=0,(n大于等于2),A1=1/2.｛an｝为等差数列已知数列｛an｝的前n项和为Sn,且满足an+2SnSn-1=0,(n大于等于2),

已知数列{an}的前n项和为Sn,且满足an+2SnSn-1=0(n≥2),a1=1/2,求an的通项公式【在线等】已知数列{an}的前n项和为Sn,且满足an+2SnSn-1=0(n≥2),a1=1

数列的通项与求和已知数列{An}的前n项和Sn满足An+2SnSn-1=0,(n大于等于2）,a1=1/2,求an数列的通项与求和已知数列{An}的前n项和Sn满足An+2SnSn-1=0,(n大于等

已知数列｛an｝的前n项和Sn满足an+2SnSn-1=0,a1=1/2,求an会的话写详细点,完了我给你加分已知数列｛an｝的前n项和Sn满足an+2SnSn-1=0,a1=1/2,求an会的话写详

已知数列{an}中,a1=1,当n>等于2时,an+2SnSn-1=0(1)求{an}的通项an已知数列{an}中,a1=1,当n>等于2时,an+2SnSn-1=0(1)求{an}的通项an已知数列

已知数列{an}的前n项和为Sn,且满足an+2SnSn-1=0(n≥2,n∈N+),a1=1/2(1)判断{1/Sn},、{An}是否是等差数已知数列{an}的前n项和为Sn,且满足an+2SnSn