如果F(x.y)=1/n^2(/2+arctanx)

y=f[(x-1)/(x+1)],f''(x)=arctanx^2,求dy/dx,dyy=f[(x-1)/(x+1)],f''(x)=arctanx^2,求dy/dx,dyy=f[(x-1)/(x+1)]

y=（x^2-1)arctanx,求n阶导数y(n)y=（x^2-1)arctanx,求n阶导数y(n)y=（x^2-1)arctanx,求n阶导数y(n)自己耐心求一下吧，x^2-1就只有三阶导数而

y=(1+x^2)arctanx微积分y=(1+x^2)arctanx微积分y=(1+x^2)arctanx微积分微分和积分是两个不同的运算,有微积分的课程,但是没有一个运算叫微积分.我估计你要几分∫

微分方程y''-y/[(1+x^2)arctanx]=arctanx的通解?微分方程y''-y/[(1+x^2)arctanx]=arctanx的通解?微分方程y''-y/[(1+x^2)arctanx]=

求(1-x^2)arctanx的导数y=(1-x^2)arctanx求(1-x^2)arctanx的导数y=(1-x^2)arctanx求(1-x^2)arctanx的导数y=(1-x^2)arcta

设z=f(x,y)=arctanx/y,y=√(x^2+1),求dz/dx设z=f(x,y)=arctanx/y,y=√(x^2+1),求dz/dx设z=f(x,y)=arctanx/y,y=√(x^

y=(1+x^2)^arctanx对y求导y=(1+x^2)^arctanx对y求导y=(1+x^2)^arctanx对y求导y=(1+x^2)^arcatanxlny=arctanx.ln(1+x^

求通解(1+x^2)y''+y=arctanx求通解(1+x^2)y''+y=arctanx求通解(1+x^2)y''+y=arctanx∵(1+x^2)y''+y=arctanx==>[(1+x^2)y''+

设fx为可导函数,y=f^2(x+arctanx),求dy/dx设fx为可导函数,y=f^2(x+arctanx),求dy/dx设fx为可导函数,y=f^2(x+arctanx),求dy/dx令u=x

f(x)=arctanx+1/2arcsinx的值域f(x)=arctanx+1/2arcsinx的值域f(x)=arctanx+1/2arcsinx的值域arctanx∈(－∏/2,∏/2)arcs

函数y=(arctanx)^2+arctanx-1的最小值为函数y=(arctanx)^2+arctanx-1的最小值为函数y=(arctanx)^2+arctanx-1的最小值为y=(arctanx

设f(x)可导,且f''(0=1,又y=f(x^2+sin^2x)+f(arctanx),求dy/dx/x=0设f(x)可导,且f''(0=1,又y=f(x^2+sin^2x)+f(arctanx),求d

证明arctanx=arcsinx/(1+x^2)^0.5.回复Y证明arctanx=arcsinx/(1+x^2)^0.5.回复Y证明arctanx=arcsinx/(1+x^2)^0.5.回复Y设

y=(1+x^2)arctanx求二阶导数y=(1+x^2)arctanx求二阶导数y=(1+x^2)arctanx求二阶导数y=(1+x²)arctanxy''=((1+x²)ar

y=sin(2x+1)+arctanx的定义域y=sin(2x+1)+arctanx的定义域y=sin(2x+1)+arctanx的定义域对于sin(2x+1),x的定义域为R对于arctanx,x的

(1+x^2)y''=arctanx,求微分方程,(1+x^2)y''=arctanx,求微分方程,(1+x^2)y''=arctanx,求微分方程,(1+x^2)y''=arctanxy''=arctanx/

1）设f(x)=2arccosx+arctanx-π,求证y＝f（x）的图像关于原点中心对称2）求满足等式arctanx＋arctan（1/y)=arctan3的正整数x,y1）设f(x)=2arcc

y=(arctanx)^2,求x=0时y的n阶导数y=(arctanx)^2,求x=0时y的n阶导数y=(arctanx)^2,求x=0时y的n阶导数y=(arctanx)^2y''=2arctanx*

y=f[(x-2)/(x+2)],f''(x)=arctanx^2,求x=0时y''y=f[(x-2)/(x+2)],f''(x)=arctanx^2,求x=0时y''y=f[(x-2)/(x+2)],f''(

已知f(x)=(arctanx)^2,则f''(x)=?已知f(x)=(arctanx)^2,则f''(x)=?已知f(x)=(arctanx)^2,则f''(x)=?f''(x)=2(arctanx)*1/