x+x^-1=3,则x^2+x^-2=?

来源:学生作业帮助网 编辑:六六作业网 时间:2024/12/25 23:41:37
x+x^-1=3,则x^2+x^-2=?x+x^-1=3,则x^2+x^-2=?x+x^-1=3,则x^2+x^-2=?x+x^-1=3,两边平方,x^2+2+x^-2=9,x^2+x^-2=7x^2

x+x^-1=3,则x^2+x^-2=?
x+x^-1=3,则x^2+x^-2=?

x+x^-1=3,则x^2+x^-2=?
x+x^-1=3,两边平方,x^2+2+x^-2=9,x^2+x^-2=7

x^2+x^-2=(x+1/x)^2-2=3^2-2=7

对原式两边同时平方....
变成x^2+x^-2 +2=9
∴x^2+x^-2=7

x+x^-1=3则(x+x^-1)²=x²+2*x*x^-1+x^-2=x^2+x^-2+2=9
所以x^2+x^-2=7

x+1/x=3,则有:x^2+1+x^-(2)=(x+1/x)^2=9,
所以x^2+x^-2=8