y=sin(2x+π/3) x∈[0,π/2] 的单调增区间以及值域.

已知sinx=3/5,x∈(π/2,π),求【sin(x+y)+sin(x-y)】/【cos（x+y）+cos（x-y）】的值 判断单调性 y=sin(x-π/6) y=sin(-2x+π/3) 求y=sin(2x+π/6)x∈(0,π/3)的值域 y=sin(x+π/3)(其中x∈[0,2π])的单调递增区间 y=sin^2x+sin (π/2-x)+3sin^2(3π/2-x)若tanx=0.5.求y值;若x∈【0,π/2】求y值域 5cos（2x-y）+7cosy=0 ,tan（x-y）tanx=?y=sin²（x+π/4)-sin²（x-π/4),x∈（π/6,π/3）值域 y=sin(x+π/3)周期 y=12sin(2x+π/6)+5sin(π/3-2x)最大值 y=12sin(2x+π/6)+5sin(π/3-2x)的最大值 y=sin(x+π/3)sin(x+π/2)化简 函数y=2sin(π/3-X)+sin(π/6+X)的最大值 周期y=sin(x+π/3)sin(x+π/2) 的最小正周期是多少 1.y=x*e^(2x) 2.y=(sin(2x))/x 3.y=sin(3x+(π/3))怎么求导数! 解微分方程：x(y´+1)+sin(x+y)=0, y(π/2)=0 已知x∈(0,π),求函数y=√3sinθ/(1+3sin^2θ)的最大值 y=sin(2x-π/3) x∈(π/2,π)求值域 y=sin(2x+π/6),x∈[π/4,3π/4]求值域 求函数的值域y=sin(2x+π/3),x∈(-π/6,π)