log2[(x-14)(x-2)]=3+log2(6-x).求x?.
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log2[(x-14)(x-2)]=3+log2(6-x).求x?.log2[(x-14)(x-2)]=3+log2(6-x).求x?.log2[(x-14)(x-2)]=3+log2(6-x).求x
log2[(x-14)(x-2)]=3+log2(6-x).求x?.
log2[(x-14)(x-2)]=3+log2(6-x).求x?.
log2[(x-14)(x-2)]=3+log2(6-x).求x?.
有题意得：x≠14,2,6
log2[(x-14)(x-2)]=3+log2(6-x)
=>log2[(x-14)(x-2)]-log2(6-x)=3
=>[(x-14)(x-2)]/(6-x)=2^3
=>(x^2-16x+28)/(6-x)=8
=>x^2-16x+28=48-8x
=>x^2-8x-20=0
=>x=10或x=2(舍去)
解方程log2(x+14)-log2(x+6)=3-log2(x+2)
log2 (x + 3) + log2(x + 2) = 1log2 (x + 3) + log2(x + 2) = 1
log2[(x-14)(x-2)]=3+log2(6-x).求x?.
求解log2(3x)=log2(2x+1)
|[log2(x)]^2-3log2(x)+1|
log2(x)=-2/3,求x
log2^(x^log2^x)=?
[log2 1]+[log2 2]+[log2 3]+[log2 4]+[log2 5]+...+[log2 1024]=?[x]表示不超过x的最大整数2为底 答案是8204
解关于x的方程：log2（x+14）-log0.5（x+2）=3+log2（x+6）
log2(4^x+4)=x+log2(2^x+1-3)log2(4^x+4)=x+log2[2^(x+1)-3]
log2(2x)*log2(x)=2 x=?
f(x)=log2(x/8)*log2(2/x)
log2(x – 2 ) + 2 = log2(5)log2(x – 2 ) + 2 = log2(5)
log2(x – 2 ) + 2 = log2(5)log2(x – 2 ) + 2 = log2(5)
log2 4+log2 (x+2)怎么算?log2 4+log2 (x+2)=log2 (4x+8)
log2（x+14）（x+2）=log2 8+log2（x+6） 2都在下面的
log2 (x+3)=-2/3
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