-1/2x^2+3/2x+2=-1/2x+b △=0 怎样解得b=4?

来源:学生作业帮助网 编辑:六六作业网 时间:2024/12/19 12:43:58
-1/2x^2+3/2x+2=-1/2x+b△=0怎样解得b=4?-1/2x^2+3/2x+2=-1/2x+b△=0怎样解得b=4?-1/2x^2+3/2x+2=-1/2x+b△=0怎样解得b=4?先

-1/2x^2+3/2x+2=-1/2x+b △=0 怎样解得b=4?
-1/2x^2+3/2x+2=-1/2x+b △=0 怎样解得b=4?

-1/2x^2+3/2x+2=-1/2x+b △=0 怎样解得b=4?
先移项得:-2分之1*X^2+2x+2-b=0,因为直线de与抛物线只有1个交点,所以△=0,则4+4*2分之1(2-b)=0,结果b=0