积分(-1,1)|x-1|x^2dx A,0 B,2∫下0上1(x∧2-x∧3)dx c,2∫下0积分(-1,1)|x-1|x^2dxA,0B,2∫下0上1(x∧2-x∧3)dxc,2∫下0上1(x∧2)dxd,2∫下0上1(x∧3-x∧2)dx

来源:学生作业帮助网 编辑:六六作业网 时间:2024/11/25 07:37:14
积分(-1,1)|x-1|x^2dxA,0B,2∫下0上1(x∧2-x∧3)dxc,2∫下0积分(-1,1)|x-1|x^2dxA,0B,2∫下0上1(x∧2-x∧3)dxc,2∫下0上1(x∧2)d

积分(-1,1)|x-1|x^2dx A,0 B,2∫下0上1(x∧2-x∧3)dx c,2∫下0积分(-1,1)|x-1|x^2dxA,0B,2∫下0上1(x∧2-x∧3)dxc,2∫下0上1(x∧2)dxd,2∫下0上1(x∧3-x∧2)dx
积分(-1,1)|x-1|x^2dx A,0 B,2∫下0上1(x∧2-x∧3)dx c,2∫下0
积分(-1,1)|x-1|x^2dx
A,0
B,2∫下0上1(x∧2-x∧3)dx
c,2∫下0上1(x∧2)dx
d,2∫下0上1(x∧3-x∧2)dx

积分(-1,1)|x-1|x^2dx A,0 B,2∫下0上1(x∧2-x∧3)dx c,2∫下0积分(-1,1)|x-1|x^2dxA,0B,2∫下0上1(x∧2-x∧3)dxc,2∫下0上1(x∧2)dxd,2∫下0上1(x∧3-x∧2)dx
选C
I=∫(-1→1)(1-x)x^2dx
= ∫(-1→1)(x^2-x^3)dx
=2∫(0→1)x^2dx-0
=2∫(0→1)x^2dx
二十年教学经验,专业值得信赖!
敬请及时采纳,在右上角点击“评价”,然后就可以选择“满意,问题已经完美解决”了.

B