x=log27(3^-2)=-2log27(3)=-2×(1/3)=-2/3 为什么是乘三分之一

log27^x=-2/3求x x=log27(1/9),求x的值这个解法哪里错了?x=log27(3^-2)=-2log27(3)=-2×3=-6 x=log27(3^-2)=-2log27(3)=-2×(1/3)=-2/3 为什么是乘三分之一 1.已知lg2=0.3010,求lg52.计算log2 3·log27 128注：log2 3 是2为低 3是真数 log2 3乘log27 125 log2 (x + 3) + log2(x + 2) = 1log2 (x + 3) + log2(x + 2) = 1 求x,y值.6log9^x+3log27^y=8log3^x+2log9^y=2 求解log2(3x)=log2(2x+1) log2 9乘以log27 8=? 其中9,8都在2和27的上方 急求高手解答 过程 解方程log2(x+14)-log2(x+6)=3-log2(x+2) [log2 1]+[log2 2]+[log2 3]+[log2 4]+[log2 5]+...+[log2 1024]=?[x]表示不超过x的最大整数2为底 答案是8204 5^log5(2)-4^log2(3)+3^log27(8)等于多少?(1)5^log5(2) - 4^log2(3) + 3^log27(8)等于多少?(2)开更号[lg2 (1/3) - 4lg(3) + 4 + lg(6) - 2^(-1)]等于多少? log2(x – 2 ) + 2 = log2(5)log2(x – 2 ) + 2 = log2(5) log2(x – 2 ) + 2 = log2(5)log2(x – 2 ) + 2 = log2(5) log2 4+log2 (x+2)怎么算?log2 4+log2 (x+2)=log2 (4x+8) log2(x)=-2/3,求x log2(2x)*log2(x)=2 x=? f(x)=log2(x/8)*log2(2/x)