化简tan(α+180度)+cos(-α)+cos(α+180度)分之sin(180度+α)-tan(-α)-tan(360度+α)

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化简tan(α+180度)+cos(-α)+cos(α+180度)分之sin(180度+α)-tan(-α)-tan(360度+α)化简tan(α+180度)+cos(-α)+cos(α+180度)分

化简tan(α+180度)+cos(-α)+cos(α+180度)分之sin(180度+α)-tan(-α)-tan(360度+α)
化简tan(α+180度)+cos(-α)+cos(α+180度)分之sin(180度+α)-tan(-α)-tan(360度+α)

化简tan(α+180度)+cos(-α)+cos(α+180度)分之sin(180度+α)-tan(-α)-tan(360度+α)
(sin(a+pi)-tan(-a)-tan(a+2pi))/(tan(a+pi)+cos(-a)+cos(a+pi))
=(-sin a+tan a-tan a)/(tan a+cos a -cos a)
=-sin a / tan a
=-cos a
答案是负cos a

tan(α+180度)+cos(-α)+cos(α+180度)分之sin(180度+α)-tan(-α)-tan(360度+α)
=tana+cosa+sina/cosa+tana-tana
=2tana+cosa

[sin(π+a)-tan(-a)-tan(2π+a)] / [tan(π+a)+cos(-a)+cos(π+a)]
=[-sina+tana-tana] / [tana+cosa-cosa]
=[-sina] / [tana]
=-cosa