函数y=cos^2(x/4)-sin^2(x/4)的最小正周期T= ?

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函数y=cos^2(x/4)-sin^2(x/4)的最小正周期T=?函数y=cos^2(x/4)-sin^2(x/4)的最小正周期T=?函数y=cos^2(x/4)-sin^2(x/4)的最小正周期T

函数y=cos^2(x/4)-sin^2(x/4)的最小正周期T= ?
函数y=cos^2(x/4)-sin^2(x/4)的最小正周期T= ?

函数y=cos^2(x/4)-sin^2(x/4)的最小正周期T= ?
y=cos^2(x/4)-sin^2(x/4)
=cos[2*(x/4)]
=cos(x/2)
所以T=2π/(1/2)==4π

y=cos^2(x/4)-sin^2(x/4)
=cos(x/2)
最小正周期T=2π/(1/2)=4π