函数y=cos^2(x/4)-sin^2(x/4)的最小正周期T= ?

来源:学生作业帮助网 编辑:六六作业网 时间:2024/07/11 12:47:30
函数y=cos^2(x/4)-sin^2(x/4)的最小正周期T=?函数y=cos^2(x/4)-sin^2(x/4)的最小正周期T=?函数y=cos^2(x/4)-sin^2(x/4)的最小正周期T

函数y=cos^2(x/4)-sin^2(x/4)的最小正周期T= ?
函数y=cos^2(x/4)-sin^2(x/4)的最小正周期T= ?

函数y=cos^2(x/4)-sin^2(x/4)的最小正周期T= ?
y=cos^2(x/4)-sin^2(x/4)
=cos[2*(x/4)]
=cos(x/2)
所以T=2π/(1/2)==4π

y=cos^2(x/4)-sin^2(x/4)
=cos(x/2)
最小正周期T=2π/(1/2)=4π