a1=1/5,an+a(n+1)=6/(5^n+1),lim(a1+a2+...an )=?
来源:学生作业帮助网 编辑:六六作业网 时间:2024/12/19 17:48:24
a1=1/5,an+a(n+1)=6/(5^n+1),lim(a1+a2+...an)=?a1=1/5,an+a(n+1)=6/(5^n+1),lim(a1+a2+...an)=?a1=1/5,an+
a1=1/5,an+a(n+1)=6/(5^n+1),lim(a1+a2+...an )=?
a1=1/5,an+a(n+1)=6/(5^n+1),lim(a1+a2+...an )=?
a1=1/5,an+a(n+1)=6/(5^n+1),lim(a1+a2+...an )=?
lim(a1+a2+...an )=a1+a2+(a3+a4)+(a5+a6)...
=6/6+6/126+6/3126+...
=6/6+6/125+6/3125+...
=1+6/125*(1/(1-1/25))
=1+6/125*(25/24)
=1+1/20
=21/20
嗨!没教呢
a1=1/5,an+a(n+1)=6/(5^n+1),lim(a1+a2+...an )=?
a1=1/5,an+a(n+1)=6/【5^(n+1)】lim(a1+a2+...an )=?
在数列{an},a1=1/5,an+a(n+1)=6/5^(n+1),n∈N+,则lim(a1+a2+...+an)的值为?
写出下列数列{an}的前5项 a1=1,a(n+1)=an+3 a1=2,a(n+1)=2an a1=3,a2=6,a(n+2)=a(n+1)-an
已知数列{an}满足a1=5,a(n+1)=an+6n+6,则an=
a1=5,n大于等于2时,an-an-1=6n,求an
a1=1,a(n+1)=6n-an,求an
数列an中,a1=6,且an-a(n-1)=a(n-1)/n+n+1,求通项公式
已知数列{An}中a1=1.且A(n+1)=6n*2^n-An.求通项公试An
数列an中 a1=0 a2=2 a(n+2)-6a(n+1)+5an=2^n 求通项an
数列{an}中a1=6 an+a(n-1)=9/an-a(n-1) +8问a70=?
已知数列{an}满足a(n+1)=an+n,a1=1,则an=
数列{an},a1=3,an*a(n+1)=(1/2)^n,求an
在数列{an}中,a1=3,a(n+1)=an+n,求an
已知数列{an}中,a(n+1)=an+2^n,a1=3,求an
数列{an}满足a1=2,a(n+1)=2an+n+2,求an
数列{an}中,a1=1/2,a(n+1)-5an=5^n,求an求解答过程
在数列{an}中 a1=1 a(n+1)+an=6n 求通项an