已知α,β∈(3/4π,π),sin(α+β)=-3/5,sin(β-π/4)=12/13,则cos(α+π/4)=?

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已知α,β∈(3/4π,π),sin(α+β)=-3/5,sin(β-π/4)=12/13,则cos(α+π/4)=?已知α,β∈(3/4π,π),sin(α+β)=-3/5,sin(β-π/4)=1

已知α,β∈(3/4π,π),sin(α+β)=-3/5,sin(β-π/4)=12/13,则cos(α+π/4)=?
已知α,β∈(3/4π,π),sin(α+β)=-3/5,sin(β-π/4)=12/13,则cos(α+π/4)=?

已知α,β∈(3/4π,π),sin(α+β)=-3/5,sin(β-π/4)=12/13,则cos(α+π/4)=?
sin(a+b)=sin(a+π/4+b-π/4).根据两角范围求cos(b-π/4)值,(sin(a+π/4))²+(cos(a+π/4))²=1关系带入数值求解方程