已知x=π/12,则sin^2x-cos^2x的值
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已知x=π/12,则sin^2x-cos^2x的值已知x=π/12,则sin^2x-cos^2x的值已知x=π/12,则sin^2x-cos^2x的值sin^2x-cos^2x=-(cos^2x-si
已知x=π/12,则sin^2x-cos^2x的值
已知x=π/12,则sin^2x-cos^2x的值
已知x=π/12,则sin^2x-cos^2x的值
sin^2x-cos^2x=-(cos ^2 x-sin^2 x)=-cos(2x)
;代入x=π/12得
sin^2x-cos^2x=-cos π/6=-√3/2
sin^2x-cos^2x=-cos2x=-cos(π/6)=-(根号3)/2
-0.5根号3
用cos倍角公式展开
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