已知cos(x+π/12)=1/3,则sin(2x-π/3)的值为多少?

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已知cos(x+π/12)=1/3,则sin(2x-π/3)的值为多少?已知cos(x+π/12)=1/3,则sin(2x-π/3)的值为多少?已知cos(x+π/12)=1/3,则sin(2x-π/

已知cos(x+π/12)=1/3,则sin(2x-π/3)的值为多少?
已知cos(x+π/12)=1/3,则sin(2x-π/3)的值为多少?

已知cos(x+π/12)=1/3,则sin(2x-π/3)的值为多少?
已知cos(x+π/12)=1/3,那么:
cos(2x+ π/6)=2cos²(x+π/12)-1=2/9 - 1=-7/9
所以:
sin(2x-π/3)=sin[(2x+ π/6)- π/2]
=-sin[π/2 -(2x+ π/6)]
=-cos(2x+ π/6)
=7/9

7/9
通过三角函数的运算解得哦
记得多背公式