sin50°(1+√ ̄3 tan10°)=

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sin50°(1+√ ̄3tan10°)=sin50°(1+√ ̄3tan10°)=sin50°(1+√ ̄3tan10°)=sin50°(1+√ ̄3tan10°)=2sin50°(sin30°+cos30

sin50°(1+√ ̄3 tan10°)=
sin50°(1+√ ̄3 tan10°)=

sin50°(1+√ ̄3 tan10°)=
sin50°(1+√ ̄3 tan10°)
= 2sin50°(sin30°+ cos30°tan10°)
= 2sin50°(sin30°cos10°+cos30°sin10°)/cos10°
= 2sin50°sin40°/cos10°
= 2cos40°sin40°/cos10°
= sin80°/cos10°
= cos10°/cos10°
= 1