sin50°(1+√ ̄3 tan10°)=

来源:学生作业帮助网 编辑:六六作业网 时间:2024/11/26 11:04:53
sin50°(1+√ ̄3tan10°)=sin50°(1+√ ̄3tan10°)=sin50°(1+√ ̄3tan10°)=sin50°(1+√ ̄3tan10°)=2sin50°(sin30°+cos30

sin50°(1+√ ̄3 tan10°)=
sin50°(1+√ ̄3 tan10°)=

sin50°(1+√ ̄3 tan10°)=
sin50°(1+√ ̄3 tan10°)
= 2sin50°(sin30°+ cos30°tan10°)
= 2sin50°(sin30°cos10°+cos30°sin10°)/cos10°
= 2sin50°sin40°/cos10°
= 2cos40°sin40°/cos10°
= sin80°/cos10°
= cos10°/cos10°
= 1