tanθ=4/3,求cos2θ=
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tanθ=4/3,求cos2θ=tanθ=4/3,求cos2θ=tanθ=4/3,求cos2θ=cos2θ=(cos²θ-sin²θ)/1=(cos²θ-sin²
tanθ=4/3,求cos2θ=
tanθ=4/3,求cos2θ=
tanθ=4/3,求cos2θ=
cos2θ=(cos²θ-sin²θ)/1=(cos²θ-sin²θ)/(sin²θ+cos²θ)=(1-tan²θ)/(tan²θ+1)=-7/25
cos2θ
=cos²θ-sin²θ
=(cos²θ-sin²θ)/(cos²θ+sin²θ)
上下除以cos²θ
=(1-tan²θ)/(1+tan²θ)
=(1-16/9)/(1+16/9)
=-7/25
tanθ=4/3,求cos2θ=
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