x-0 x^2sin(1/x)/sinx

sinx/x,(sinx/x)^2,sin(x^2)/(x^2)的大小 x∈(0,1] x-0 x^2sin(1/x)/sinx 求极限 （（sin(x^3+x^2-x)+sin x) /x x→0 已知lim sinx/x=1 lim(1+sinx-sin(sinx))^x^-3 x趋于0 (sin^x/sinx-cosx)-sinx+cosx/tan^2x-1 1-2sinx*sin(60+x)sin(60-x) (tanx-sinx)/x^2sin^2x 极限x--->0 sinx>sin(2π/3-x)（0 cosx-sinx/1+sin^2x不定积分 sinx/(1+sin^2x)的积分 sin(sinx)/x,x 趋于0的极限sin(sin(x))/x=[sin(sin(x))/sin(x)]*sin(x)/x=1*1=1sin(sin(x))/sin(x)这一部我不明白阿 sinx+sin-x= S(1-sin^2x)d(sinx)为什么=sinx-1/3sin^3x? sinx*( cos x)^3/(1+sin^2x)的不定积分 |sin(x+Δx)-sinx| 求证 sin^2x/(sinx-cosx)-(sinx+cosx)/tan^2 x-1=sinx+cosx 化简[sin^2(x)]/(sinx-cosx)-(sinx+cosx)/[tan^2(x)-1]-sinx lim(x^2sin(1/x))/sinx=?不好意思，忘写了，x->0