∫ 1/2cos(x/2)dx=?x>π/3

∫(2/cos^2x)dx= ∫(1-cos^(2)2x)dx ∫1/(1+cos^2(x)) dx ∫cos(x+2)dx=多少 ∫(1+sinx) / cos^2 x dx 不定积分cos(x^1/2)dx=? cos(x^2)dx ∫x*(cos^2x)dx ∫x／[(cos^2)x]dx ∫sin(x) cos^2(x)dx ∫cos(2x+1)^5dx=? 微积分1/cos^2(x)dx=?微积分1/cos^2(x)dx＝? ∫ 1/2cos(x/2)dx=?x>π/3 ∫ 1/2cos(x/2)dx=?x>π/3 计算∫π/4~0 x/cos^2x dx ∫cos x / ( 1 + (sinx)^2 ) dx = ∫x^3 / ( 1 + x^4 ) dx = ∫(sec x)^3 * tan x dx = ∫x^2 * e^(-2x) dx = ∫x * cos 2x dx = ∫(cos 2x)^2 dx = ∫(13x - 6) / ( x (x-2)(x+3) )dx = ∫(x^2 + 2x - 2) / ((x-2)(x+1)) dx = 请把过程写出来哈.>< 旷 这个怎恶魔算∫cos x / ( 1 + (sinx)^2 ) dx = ∫x^3 / ( 1 + x^4 ) dx = ∫(sec x)^3 * tan x dx = ∫x^2 * e^(-2x) dx = ∫x * cos 2x dx = ∫(cos 2x)^2 dx = ∫(13x - 6) / ( x (x-2)(x+3) )dx = ∫(x^2 + 2x - 2) / ((x-2)(x+1)) dx = ∫(1+sin^2x)/(cos^2x)dx