求y=(x-3)/(x+3)的值域rt

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求y=(x-3)/(x+3)的值域rt求y=(x-3)/(x+3)的值域rt求y=(x-3)/(x+3)的值域rt答:y=(x-3)/(x+3)=(x+3-6)/(x+3)=1-6/(x+3)6/(x

求y=(x-3)/(x+3)的值域rt
求y=(x-3)/(x+3)的值域
rt

求y=(x-3)/(x+3)的值域rt
答:
y=(x-3)/(x+3)
=(x+3-6)/(x+3)
=1-6/(x+3)
6/(x+3)=1-y≠0
所以:y≠1
所以:值域为(-∞,1)∪(1,+∞)