n→0时,求limn[ln(n 2)-lnn]
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n→0时,求limn[ln(n2)-lnn]n→0时,求limn[ln(n2)-lnn]n→0时,求limn[ln(n2)-lnn]limn[ln(n2)-lnn]=limnln(n)=limln(n
n→0时,求limn[ln(n 2)-lnn]
n→0时,求limn[ln(n 2)-lnn]
n→0时,求limn[ln(n 2)-lnn]
limn[ln(n 2)-lnn]
=limnln(n)
=lim ln(n)/(1/n)
利用洛必达法则
原式
=lim (1/n)/(-1/n^2)
=lim(-n)
=0
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