π/2<2x+π/3<2π/3 如何变成 ?<sin(2x+π/3)<?
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π/2<2x+π/3<2π/3如何变成?<sin(2x+π/3)<?π/2<2x+π/3<2π/3如何变成?<sin(2x+π/3)<?π/2<2x+π/3<2π/3如何变成?<sin(2x+π/3)
π/2<2x+π/3<2π/3 如何变成 ?<sin(2x+π/3)<?
π/2<2x+π/3<2π/3 如何变成 ?<sin(2x+π/3)<?
π/2<2x+π/3<2π/3 如何变成 ?<sin(2x+π/3)<?
设函数f(x)=sin(2x+π/3)
定义域为 π/2<2x+π/3<2π/3
因为sinx在π/2<x<2π/3上是减函数
所以sin3π/2<sin(2x+π/3)<sinπ/2
即√3/2 <sin(2x+π/3)<1
(√3/2,1)
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