1/(sin^4 xcos^4 x)积分

1/(sin^4 xcos^4 x)积分 求定积分∫(1/sin^2xcos^2x)dx上标派/3下标派/4 积分 sin^4xcos^2x dx利用三角学解以下积分(如图)Hints:sin^4xcos^2x = sin^2x(sinxcosx)^2 1/(sin^4xcos^4x)的不定积分 (1-(sin^4x-sin^2xcos^2x+cos^4x)/sin^2x +3sin^2x 化简[1-(sin^4 x-sin^2 xcos^2 x+cos^4 x)]/(sin^2 x)+3sin^2 x 求证sin^4x+cos^4x=1-2sin^2xcos^2x sin^4x+cos^4x=1-2sin^2Xcos^2X谢谢额 求证 sinˇ4X+sin²Xcos²X+cos²X = 1 sin^4+sin^2xcos^2x+cos^2x 证明 =1 请帮我求四道积分~1.∫(5x+1)^e^5x dx 积分上限是4,积分下限是02. ∫e^∏xcos∏xdx 积分上限是1, 积分下限是03. ∫x/(sin^2x)dx积分上限是∏/3, 积分下限是∏/44. ∫xarctanxdx积分上限是1, 积分下限是0不要 sin^8X+cos^8X+4sin^2Xcos^2x-2sin^4xcos^4X(化简） 求sin^4x+cos^4x+4sin^2xcos^2x-1的最小正周期及值域. 求sin^4x+cos^4x+4sin^2xcos^2x-1的最小正周期及值域. 求sin^4x+cos^4x=1-2sin^2xcos^2x的详细答案! 求定积分∫上限π/2,下限0 4sin^2xcos^2xdx, y=1-4sin²xcos²x的导数y'= ∫1/(sin^2xcos^2x)