求sin^4x+cos^4x+4sin^2xcos^2x-1的最小正周期及值域.
来源:学生作业帮助网 编辑:六六作业网 时间:2024/12/25 00:16:36
求sin^4x+cos^4x+4sin^2xcos^2x-1的最小正周期及值域.求sin^4x+cos^4x+4sin^2xcos^2x-1的最小正周期及值域.求sin^4x+cos^4x+4sin^
求sin^4x+cos^4x+4sin^2xcos^2x-1的最小正周期及值域.
求sin^4x+cos^4x+4sin^2xcos^2x-1的最小正周期及值域.
求sin^4x+cos^4x+4sin^2xcos^2x-1的最小正周期及值域.
y=sin^4x+cos^4x+4sin^2xcos^2x-1
=(sin^2x+cos^2x)^2+2sin^2xcos^2x-1
=1+2sin^2xcos^2x-1
=2sin^2xcos^2x
=1/2*sin^2(2x)
=(1-cos4x)/4
=1/4-1/4*cos4x
周期T=2π/4=π/2
值域是:[0,1/2]
如果你认可我的回答,请点击左下角的“采纳为满意答案”,祝学习进步!
手机提问的朋友在客户端右上角评价点【满意】即可
化简sin^4x-sin^2x+cos^2x
化简:sin^4 x-sin^2 x+cos^2 x
求∫1/(sin^4x+cos^4x)dx,
sin^4x+cos^4x怎么求导数?
求4sin(3x)cos(x)的导数式如题
求微积分 ∫sin^2(x)cos^4(x) dx
化简cos^4x+sin^4x
化简:cos^4(X)-sin^4(X)
化简sin^4x+cos^2x
化简(sin^2x-cos^4x+cos^2x-sin^4x)/(sin^2x-cos^6x+cos^2x-sin^6x)
化简[1-(sin^4x-sin^2cos^2x+cos^4x)/(sin^2)]+3sin^2x
求(1-sin^6x-cos^6x)/(1-sin^4x-cos^4x)的值
求1-cos^6x-sin^6x/1-cos^4x-sin^4x的值,
[(sin x-cos x)/(sin x+cos x)]^4 求定积分 积分区间0-π/4
求证明.关于cos和sin 题目有点长0 0【cos(2x) + cos(4x) + cos(6x)】 / 【sin(2x) + sin(4x) + sin(6x) 】 = cot(4x)
(1-(sin^4x-sin^2xcos^2x+cos^4x)/sin^2x +3sin^2x
化简[1-(sin^4 x-sin^2 xcos^2 x+cos^4 x)]/(sin^2 x)+3sin^2 x
求证(cos^2 x-sin^2 x)(cos^4 x+sin^4 x)+1/4 sin 2x sin 4x=cos 2x