如图,△ABC中,角acb=90°,以ac为边向三角形外作正方形如图,△abc中,角acb=90°,以ac为边向三角形外作正方形acde,be交ac于f,过f作fg平行于cb,交ab于g,求证fc=fg1楼的大哥,
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如图,△ABC中,角acb=90°,以ac为边向三角形外作正方形如图,△abc中,角acb=90°,以ac为边向三角形外作正方形acde,be交ac于f,过f作fg平行于cb,交ab于g,求证fc=fg1楼的大哥,
如图,△ABC中,角acb=90°,以ac为边向三角形外作正方形
如图,△abc中,角acb=90°,以ac为边向三角形外作正方形acde,be交ac于f,过f作fg平行于cb,交ab于g,求证fc=fg
1楼的大哥,
如图,△ABC中,角acb=90°,以ac为边向三角形外作正方形如图,△abc中,角acb=90°,以ac为边向三角形外作正方形acde,be交ac于f,过f作fg平行于cb,交ab于g,求证fc=fg1楼的大哥,
这个……不知道题目有没有规定不可以用代数方法解答……
如图:GF/BC=AF/AC=(AC-FC)/AC
FC/ED=BC/BD=BC/(BC+CD)
我们将正方形边长设为定值a
带入a可得 GF/BC=(a-FC)/a
FC/a=BC/(BC+a)
带换掉BC可得
a*FC/(a-FC)=a*GF/(a-FC)
既得结论 FC=GF
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