若x-y=9,xy=7/4,则x+y=?
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若x-y=9,xy=7/4,则x+y=?若x-y=9,xy=7/4,则x+y=?若x-y=9,xy=7/4,则x+y=?(x+y)^2=(x-y)^2+4xy=88所以x+y=+-√88=+-2√22
若x-y=9,xy=7/4,则x+y=?
若x-y=9,xy=7/4,则x+y=?
若x-y=9,xy=7/4,则x+y=?
(x+y)^2=(x-y)^2+4xy=88
所以x+y=+-√88=+-2√22
(x-y)^+4xy=(x+y)^
答案应该是正负89开根号
x-y=9
两边平方 x^2-2xy+y^2=81
两边加上4xy x^2+2xy+y^2=81+4xy=81+7=89
配方 (x+y)^2=89
开方 x+y=±√89
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