极限x趋近于无穷(x-1/x+2)^x+1求极限

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极限x趋近于无穷(x-1/x+2)^x+1求极限极限x趋近于无穷(x-1/x+2)^x+1求极限极限x趋近于无穷(x-1/x+2)^x+1求极限(x-1)/(x+2)=1-3/(x+2)令a=-3/(

极限x趋近于无穷(x-1/x+2)^x+1求极限
极限x趋近于无穷(x-1/x+2)^x+1
求极限

极限x趋近于无穷(x-1/x+2)^x+1求极限
(x-1)/(x+2)
=1-3/(x+2)
令a=-3/(x+2)
x+1=-3a-1
原式=lim(1+1/a)^(-3a)÷(1+1/a)
=lim[(1+1/a)^a]^(-3)÷(1+1/a)
=e^(-3)÷1
=1/e³

你这个题目表达有歧义

(x-1/x+2)^x+1=(1-3/(x+2))^x+1=1^x+1=2
x趋于无穷 3/(x+2)趋于0 括号里的数字趋于1

猜测你漏了3个括号
[(x-1)/(x+2)]^(x+1)
=[1-3/(x+2)]^(x+1)
={[1-1/(x/3+2/3)]^(x/3+2/3)}^[(x+1)/(x/3+2/3)]
然后取极限
令t=x/3+2/3->无穷
原式=[(1-1/t)^(t)]^[(3t-1)/t]
底数的极限是e^(-1)
指数极限=3-1/t=3
所以答案是[e^(-1)]^3=e^(-3)