求2^nsinx/2^n在n趋向于无穷的时候的极限

求2^nsinx/2^n在n趋向于无穷的时候的极限 lim2^nsinx/2^n,n--无穷求详解 lim[(根号下n^2+n)-n],n趋向于无穷,求函数的极限 当n趋向于无穷时,求n^(1/2)*[n^(1/n)-1]的极限 lim(n/(n^2+1)+...+n/(n^2+n))x趋向于无穷 求解答过程~ f(x)=lim[(nsinx +1）/(n+2)x] n趋于无穷 求f(x)表达式 求lim趋向于无穷3^n+(-2)^n/3^(n+1)+(-2)^(n+1) 求极限 n趋向于无穷 lim（(根号下n^2+1)/(n+1)）^n 求极限lim(n趋向于无穷）(n+1)(根号下(n^2+1)-n) 求极限:Lim(1+1/n-1/n^2)^n n趋向于正无穷 求极限(1/n^2)/(e^(1/n)-1-1/n) n趋向于无穷 求极限 lim（ √N^2+N ）－N X趋向于无穷 求极限 n趋向于无穷 求极限 lim（n趋向于无穷）2^n/n! n^2/3^n当n趋向于无穷时求极限 求极限lim n趋向于无穷（1/n）*√(n+1)(n+2)⋯(n+n) （2＋（2／3）^1／n)^n,求当n趋向于正无穷的极限 当x趋向于正无穷,求lim{（根号((n^2)+1)）/(n+1)}^n的极限